Enzyme Kinetics

Derivation of Kcat or Turnover Number


For all enzyme catalyzed reactions

[Et] <-> [ES] + [E]

The highest rate obtainable is when the enzyme is saturated with substrate, i.e. at high [S]. Then [ES] = [Et]

Vmax = k3[Et]; and  k3

 = Vmax/[Et]

for this reason, k3, which is also called Kcat when the enzyme is saturated, is referred to as the turnover number, and

Vmax = kcat[Et]; and  kcat

 = Vmax/[Et]

Equation 1

When [S] is low, [E] is about equal to [[Et]]

Therefore, at low [S], from Equation 1 and the Michaelis-Menten equation, since

Missing Image

Consider the situation where we have an enzyme and two different substrates A and B. If the concentration of the enzyme is the same in both reactions it can be shown that

(vA/vB) = {(kcat/Km)A[A]}/{(kcat/Km)B[B]}

Therefore, Kcat/Km is a measure of how rapidly an enzyme works at low [S] and is referred to as the specificity constant. It is a means of comparing substrates, i.e. studying the specificity of and enzyme. For chymotrypsin with N-acetyl amino acid methyl esters as the substrates the values for Gly and Phe vary by about 1 million, explaining the specificity of this enzyme. Note that the upper limit of kcat/Km is about 10^9 M^-1 sec^-1, which is enzymatic perfection. Substrate cannot diffuse to the enzyme any faster.


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